I've just started learning Haskell and I've been wondering about this issue
as well. I can usually work out a point-free version by carefullty deriving it step-by-step, but I was wondering if Haskell had composition operators/functions for dealing with the various forms of composition where a 2-arg function is involved. I've played around with J (APL's successor) a little and noticed that J has various options for composing two functions (Ponit-free, or "implicit" style is very important in J). Some of the distinctions have to do with J's native array operations and aren't relevant here, but many are. Here are Haskell versions... (note: "monadic" below isn't used in the Haskell/CT sense - "monadic" and "dyadic" in J jsut refer to how many arguments an operator acts on) -- hook is the J dyadic hook as a function. hook :: (a->b->c) -> (d->b) -> a -> d -> c hook f g = \x y -> f x (g y) -- J's monadic hook mhook :: (a->b->c) -> (a->b) -> a -> c mhook f g = \x -> (hook f g) x x -- J's monadic fork fork :: (a->b->c) -> (d->a) -> (d->b) -> d -> c fork f g h = \x -> f (g x) (h x) -- J's dyadic fork dyfork :: (a->b->c) -> (d->e->a) -> (d->e->b) -> d -> e -> c dyfork f g h = \x y -> f (g x y) (h x y) -- J's dyadic @ or @: - composition of 1-arg fn with 2-arg fn compose12 :: (a->b) -> (c->d->a) -> c -> d -> b compose12 f g = \x y -> f (g x y) (@:) = compose12 {- J's dyadic & or &: - composition of 2-arg fn with 1-arg fn, resulting in a 2-arg fn (f&:g) which applies g to *both* args before passing them to f. Haskell's composition operator and partial application allow a composition of such fns (f . g) where g is applied only to the first arg. -} compose21 :: (a->a->b) -> (c->a) -> c -> c -> b compose21 f g = \x y -> f (g x) (g y) (&:) = compose21 / /I know a lot of Haskell is written in point-free style and I would have thought Haskell would have operators for some of this, but judging from the previous responses, it looks like it might not. That surprises me, since some of this seems to crop up a lot, but as I said I've just started learning Haskell, so I guess I'll have to give myself some time to absorb the Haskell way of doing things. -------------- next part -------------- An HTML attachment was scrubbed... URL: http://www.haskell.org/pipermail/beginners/attachments/20090703/2179c1d6/attachment.html |
Functions in Haskell aren't distinguished as 1-arg of 2-arg functions.
Usually we don't even think of them as such -- rather we think of the type of the function or operator. But there is a wide array of combinators available: K = const I = id B = (.) C = flip S = Monad.ap -- instance Monad (->) a - the Reader Monad W = Monad.join -- also for the Reader Monad Y = Control.Monad.Fix.fix and the list goes on and on... Using only S and K, a great many functions can be expressed, though it does get rather ugly. Perhaps the most significant reason that Haskell doesn't have more composition operators is that composing functions is the least part of what we compose. Using some standard class functions often yields exactly what you're looking for: hook = liftM2 (.) mhook = ap fork = liftM2 dyfork = liftM2 . liftM2 compose12 = (.) (.) (.) -- as previously shown Written in this form, the first four become far more general: "hook" is function composition within a monad; "mhook" is function application within a monad; "fork" raises a function for application on monads; and "dyfork" -- absolutely beautiful, BTW -- raises a function for application upon nested monads. BTW, if anyone has a reasonably concise form for a point-free compose21, I'd like to see it. On Fri, Jul 3, 2009 at 7:15 PM, Troy Pracy <[hidden email]> wrote: > I've just started learning Haskell and I've been wondering about this issue > as well. I can usually work out a point-free version by carefullty deriving > it step-by-step, but I was wondering if Haskell had composition > operators/functions for dealing with the various forms of composition where > a 2-arg function is involved. > > I've played around with J (APL's successor) a little and noticed that J has > various options for composing two functions (Ponit-free, or "implicit" style > is very important in J). Some of the distinctions have to do with J's > native array operations and aren't relevant here, but many are. Here are > Haskell versions... > (note: "monadic" below isn't used in the Haskell/CT sense - "monadic" and > "dyadic" in J jsut refer to how many arguments an operator acts on) > > -- hook is the J dyadic hook as a function. > hook :: (a->b->c) -> (d->b) -> a -> d -> c > hook f g = \x y -> f x (g y) > -- J's monadic hook > mhook :: (a->b->c) -> (a->b) -> a -> c > mhook f g = \x -> (hook f g) x x > -- J's monadic fork > fork :: (a->b->c) -> (d->a) -> (d->b) -> d -> c > fork f g h = \x -> f (g x) (h x) > -- J's dyadic fork > dyfork :: (a->b->c) -> (d->e->a) -> (d->e->b) -> d -> e -> c > dyfork f g h = \x y -> f (g x y) (h x y) > -- J's dyadic @ or @: - composition of 1-arg fn with 2-arg fn > compose12 :: (a->b) -> (c->d->a) -> c -> d -> b > compose12 f g = \x y -> f (g x y) > (@:) = compose12 > {- J's dyadic & or &: - composition of 2-arg fn with 1-arg fn, resulting > in a > 2-arg fn (f&:g) which applies g to *both* args before passing them to f. > Haskell's composition operator and partial application allow a > composition > of such fns (f . g) where g is applied only to the first arg. -} > compose21 :: (a->a->b) -> (c->a) -> c -> c -> b > compose21 f g = \x y -> f (g x) (g y) > (&:) = compose21 > > > / /I know a lot of Haskell is written in point-free style and I would have > thought Haskell would have operators for some of this, but judging from the > previous responses, it looks like it might not. That surprises me, since > some of this seems to crop up a lot, but as I said I've just started > learning Haskell, so I guess I'll have to give myself some time to absorb > the Haskell way of doing things. > _______________________________________________ > Beginners mailing list > [hidden email] > http://www.haskell.org/mailman/listinfo/beginners > > An HTML attachment was scrubbed... URL: http://www.haskell.org/pipermail/beginners/attachments/20090704/69375793/attachment.html |
Note here that where liftM2 and ap are used, we can be more general
than monads -- we need only Applicatives instead, substituting liftA2 and <*> instead. Also, compose12 can be made more general using (fmap . fmap), and becomes the two level fmap -- instead of applying the function inside one layer of functor it goes two layers in. Similarly with hook, we can use liftA2 fmap, and be generalised over all functors, not just functions. Bob On 4 Jul 2009, at 11:15, Geoffrey Marchant wrote: > Functions in Haskell aren't distinguished as 1-arg of 2-arg > functions. Usually we don't even think of them as such -- rather we > think of the type of the function or operator. > > But there is a wide array of combinators available: > > K = const > I = id > B = (.) > C = flip > S = Monad.ap -- instance Monad (->) a - the Reader Monad > W = Monad.join -- also for the Reader Monad > Y = Control.Monad.Fix.fix > > and the list goes on and on... Using only S and K, a great many > functions can be expressed, though it does get rather ugly. > > Perhaps the most significant reason that Haskell doesn't have more > composition operators is that composing functions is the least part > of what we compose. Using some standard class functions often yields > exactly what you're looking for: > > hook = liftM2 (.) > mhook = ap > fork = liftM2 > dyfork = liftM2 . liftM2 > compose12 = (.) (.) (.) -- as previously shown > > Written in this form, the first four become far more general: > > "hook" is function composition within a monad; > "mhook" is function application within a monad; > "fork" raises a function for application on monads; and > "dyfork" -- absolutely beautiful, BTW -- raises a function for > application upon nested monads. > > BTW, if anyone has a reasonably concise form for a point-free > compose21, I'd like to see it. > > > On Fri, Jul 3, 2009 at 7:15 PM, Troy Pracy <[hidden email]> wrote: > I've just started learning Haskell and I've been wondering about > this issue as well. I can usually work out a point-free version by > carefullty deriving it step-by-step, but I was wondering if Haskell > had composition operators/functions for dealing with the various > forms of composition where a 2-arg function is involved. > > I've played around with J (APL's successor) a little and noticed > that J has various options for composing two functions (Ponit-free, > or "implicit" style is very important in J). Some of the > distinctions have to do with J's native array operations and aren't > relevant here, but many are. Here are Haskell versions... > (note: "monadic" below isn't used in the Haskell/CT sense - > "monadic" and "dyadic" in J jsut refer to how many arguments an > operator acts on) > > -- hook is the J dyadic hook as a function. > hook :: (a->b->c) -> (d->b) -> a -> d -> c > hook f g = \x y -> f x (g y) > -- J's monadic hook > mhook :: (a->b->c) -> (a->b) -> a -> c > mhook f g = \x -> (hook f g) x x > -- J's monadic fork > fork :: (a->b->c) -> (d->a) -> (d->b) -> d -> c > fork f g h = \x -> f (g x) (h x) > -- J's dyadic fork > dyfork :: (a->b->c) -> (d->e->a) -> (d->e->b) -> d -> e -> c > dyfork f g h = \x y -> f (g x y) (h x y) > -- J's dyadic @ or @: - composition of 1-arg fn with 2-arg fn > compose12 :: (a->b) -> (c->d->a) -> c -> d -> b > compose12 f g = \x y -> f (g x y) > (@:) = compose12 > {- J's dyadic & or &: - composition of 2-arg fn with 1-arg fn, > resulting in a > 2-arg fn (f&:g) which applies g to *both* args before passing them > to f. > Haskell's composition operator and partial application allow a > composition > of such fns (f . g) where g is applied only to the first arg. -} > compose21 :: (a->a->b) -> (c->a) -> c -> c -> b > compose21 f g = \x y -> f (g x) (g y) > (&:) = compose21 > > > / /I know a lot of Haskell is written in point-free style and I > would have thought Haskell would have operators for some of this, > but judging from the previous responses, it looks like it might not. > That surprises me, since some of this seems to crop up a lot, but as > I said I've just started learning Haskell, so I guess I'll have to > give myself some time to absorb the Haskell way of doing things. > _______________________________________________ > Beginners mailing list > [hidden email] > http://www.haskell.org/mailman/listinfo/beginners > > > _______________________________________________ > Beginners mailing list > [hidden email] > http://www.haskell.org/mailman/listinfo/beginners |
In reply to this post by Geoffrey Marchant
Found it:
compose21 = Data.Function.on Which makes the complete list, with Thomas Davie's changes: hook = liftA2 fmap mhook = <*> fork = liftA2 dyfork = liftA2 . liftA2 compose12 = fmap . fmap compose21 = on On Sat, Jul 4, 2009 at 3:15 AM, Geoffrey Marchant < [hidden email]> wrote: > Functions in Haskell aren't distinguished as 1-arg of 2-arg functions. > Usually we don't even think of them as such -- rather we think of the type > of the function or operator. > But there is a wide array of combinators available: > > K = const > I = id > B = (.) > C = flip > S = Monad.ap -- instance Monad (->) a - the Reader Monad > W = Monad.join -- also for the Reader Monad > Y = Control.Monad.Fix.fix > > and the list goes on and on... Using only S and K, a great many functions > can be expressed, though it does get rather ugly. > > Perhaps the most significant reason that Haskell doesn't have more > composition operators is that composing functions is the least part of what > we compose. Using some standard class functions often yields exactly what > you're looking for: > > hook = liftM2 (.) > mhook = ap > fork = liftM2 > dyfork = liftM2 . liftM2 > compose12 = (.) (.) (.) -- as previously shown > > Written in this form, the first four become far more general: > > "hook" is function composition within a monad; > "mhook" is function application within a monad; > "fork" raises a function for application on monads; and > "dyfork" -- absolutely beautiful, BTW -- raises a function for application > upon nested monads. > > BTW, if anyone has a reasonably concise form for a point-free compose21, > I'd like to see it. > > > On Fri, Jul 3, 2009 at 7:15 PM, Troy Pracy <[hidden email]> wrote: > >> I've just started learning Haskell and I've been wondering about this >> issue as well. I can usually work out a point-free version by carefullty >> deriving it step-by-step, but I was wondering if Haskell had composition >> operators/functions for dealing with the various forms of composition where >> a 2-arg function is involved. >> >> I've played around with J (APL's successor) a little and noticed that J >> has various options for composing two functions (Ponit-free, or "implicit" >> style is very important in J). Some of the distinctions have to do with J's >> native array operations and aren't relevant here, but many are. Here are >> Haskell versions... >> (note: "monadic" below isn't used in the Haskell/CT sense - "monadic" and >> "dyadic" in J jsut refer to how many arguments an operator acts on) >> >> -- hook is the J dyadic hook as a function. >> hook :: (a->b->c) -> (d->b) -> a -> d -> c >> hook f g = \x y -> f x (g y) >> -- J's monadic hook >> mhook :: (a->b->c) -> (a->b) -> a -> c >> mhook f g = \x -> (hook f g) x x >> -- J's monadic fork >> fork :: (a->b->c) -> (d->a) -> (d->b) -> d -> c >> fork f g h = \x -> f (g x) (h x) >> -- J's dyadic fork >> dyfork :: (a->b->c) -> (d->e->a) -> (d->e->b) -> d -> e -> c >> dyfork f g h = \x y -> f (g x y) (h x y) >> -- J's dyadic @ or @: - composition of 1-arg fn with 2-arg fn >> compose12 :: (a->b) -> (c->d->a) -> c -> d -> b >> compose12 f g = \x y -> f (g x y) >> (@:) = compose12 >> {- J's dyadic & or &: - composition of 2-arg fn with 1-arg fn, resulting >> in a >> 2-arg fn (f&:g) which applies g to *both* args before passing them to f. >> Haskell's composition operator and partial application allow a >> composition >> of such fns (f . g) where g is applied only to the first arg. -} >> compose21 :: (a->a->b) -> (c->a) -> c -> c -> b >> compose21 f g = \x y -> f (g x) (g y) >> (&:) = compose21 >> >> >> / /I know a lot of Haskell is written in point-free style and I would have >> thought Haskell would have operators for some of this, but judging from the >> previous responses, it looks like it might not. That surprises me, since >> some of this seems to crop up a lot, but as I said I've just started >> learning Haskell, so I guess I'll have to give myself some time to absorb >> the Haskell way of doing things. >> _______________________________________________ >> Beginners mailing list >> [hidden email] >> http://www.haskell.org/mailman/listinfo/beginners >> >> > An HTML attachment was scrubbed... URL: http://www.haskell.org/pipermail/beginners/attachments/20090704/871bec0a/attachment.html |
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